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isn't there a method called packet fragmentation?
I have been looking for papers on this method a long time, but no success.
In this method you just connect to the open port (eg. 80) and by messing with the data in the packets you send to port 80, you can get access to another port (that is closed/filtered) like port 23 or 21.
If you want, I could dig up some more info about this ;) (but after the 19th, because I have midterms right now) :p
Yeah, it's for bypassing firewall. Isn't that what you mean?
In this method you just connect to the open port (eg. 80) and by messing with the data in the packets you send to port 80, you can get access to another port (that is closed/filtered) like port 23 or 21.
If you want, I could dig up some more info about this ;) (but after the 19th, because I have midterms right now) :p
Yeah, it's for bypassing firewall. Isn't that what you mean?
I am well Aware that fragmentation can be used to bypass the restrictions on the
IPS AND firewalls,but i am not looking for that,i am much interested in achieving
this
In this method you just connect to the open port (eg. 80) and by messing with the data in the packets you send to port 80, you can get access to another port (that is closed/filtered) like port 23 or 21.
If you want, I could dig up some more info about this ;) (but after the 19th, because I have midterms right now) :p
Hope you got my question,and as i said i would be glad if i get some links related to this method...
hope i will get some help from you :)
A fellow perl coder?
maybe i am not reading this right, but how does one \"open\" a closed port? to open a port would mean to initiate a running SERVICE. i don't believe one can just force a service to magically start running if it is not there to create the socket and port (unless there is a payload sent to create it--dll injection/etc). even with fragmentation, i don't believe this is even close to possible. i think that the fragmentation method would simply be used to bypass ACL policies on the firewall through source/destination misdirection with the packets being marshalled at the other end. i still don't see how this \"opens\" a port that doesn't exist